HP Forums

The current implementation for vandermond(v) simply returns a square matrix based on a vector v. So if v has n entries, vandermond(v) is an n x n matrix. Is it possible to have vandermonde also accept an optional argument m so that vandermonde(v,m) returns an m x n matrix?

I second, +1!

I would return an n rows x m column matrix according to the current convention, not n x m