Hello compsystems,
Your expression
Quote:solve( ∫( (1/(√(2*π)*s))*e^(-(t-u)^2/(2*s^2)),t, t,∞), t=0.1 )
looks odd because you're using the same name "
t" for two different variables. You should rename one of them (either the red or blue), e.g. to τ (tau).
(1)
t within the integrand refers to the integration variable
t.
(2)
t to be solved refers to the integration lower limit
t.
(3)
t and
t are two distinct variables (each having their own context/scope/lifetime).
So you are trying to find a lower integration limit
t (somewhere near 0.1) so that the integral becomes zero (the to-solve-equation is implicitly set to =0), which would only hold if both limits are equal (since your integrand has everywhere the same sign).
But your expression differs from that of
factor. Look at his screenshots:
Quote:solve( ∫( (1/(√(2*π)*s))*e^(-(t-u)^2/(2*s^2))=0.1, t, t, ∞), s )
Here we have two distinct
t again. Now we're searching for
s so that the integral becomes 0.1. Since the lower limit
t is a free variable the result depends on whatever
t is set to.
Hello factor,
I do not know the original problem, but I think the lower limit should not be t but something like either 0 or -∞. (On your calc you seem to have set t to 40, which becomes the lower integration limit). Maybe you're not searching for an s but for t as compsystems suggested (if so, don't name your integration variable also t since it's not forbidden but a bit confusing).
Furthermore I doubt the Prime is able to solve that integral. You should paraphrase it in terms of "erf"/"erfc"/"NORMALD_CDF"/"NORMALD_ICDF" functions and set your lower integration limit and
u to concrete values before solving numerically.