11-20-2023, 12:41 PM
Function ierfc(z)
Wolfram Alpha defines it as
z×erfc(z) - e^(-z²)/sqrt(pi)
and calculates accordingly.
At Wikipedia, French version,
of Function d'erreur, section "Extensions",
we find the reverse definition, ie:
e^(-z²)/sqrt(pi) - z×erfc(z).
Is there an "error" here?
What is the most common convention or the "correct" definition ?
Thanks for your answer.
Wolfram Alpha defines it as
z×erfc(z) - e^(-z²)/sqrt(pi)
and calculates accordingly.
At Wikipedia, French version,
of Function d'erreur, section "Extensions",
we find the reverse definition, ie:
e^(-z²)/sqrt(pi) - z×erfc(z).
Is there an "error" here?
What is the most common convention or the "correct" definition ?
Thanks for your answer.