04-27-2023, 11:35 PM
Suppose the following program
« { } 2 5
FOR i i a ^ +
NEXT
»
Its execution gives
{ '2^a' '3^a' '4^a' '5^a' } <1>
Now
'n^a' n 2 4 1 SEQ
gives { 'EXP(a*LN(2))' 'EXP(a*LN(3))' 'EXP(2*a*LN(2))'} <2>
Using SEQ
how can I get the form given in <1>
(with no LN)?
« { } 2 5
FOR i i a ^ +
NEXT
»
Its execution gives
{ '2^a' '3^a' '4^a' '5^a' } <1>
Now
'n^a' n 2 4 1 SEQ
gives { 'EXP(a*LN(2))' 'EXP(a*LN(3))' 'EXP(2*a*LN(2))'} <2>
Using SEQ
how can I get the form given in <1>
(with no LN)?