03-06-2019, 01:26 PM
The programs LSM (left-shift matrix) and RSM (right-shift matrx) create a n x n matrix based on the elements of a given list. Each row has each of the elements rotated one element.
For LSM, each row has the elements shifted to the left one element.
For RSM, each row has the elements shifted to the right one element.
HP Prime Program: LSM
HP Prime Program: RSM
Note: The program RSM creates a circulant matrix.
Example:
list = {1, 7, 8, -2, 0}
LSM({1, 7, 8, -2, 0} returns:
[ [ 1, 7, 8, -2, 0 ]
[ 7, 8, -2, 0, 1 ]
[ 8, -2, 0, 1, 7 ]
[ -2, 0, 1, 7, 8 ]
[ 0, 1, 7, 8, -2 ] ]
RSM({1,7,8,-2,0}) returns:
[ [ 1, 7, 8, -2, 0 ]
[ 0, 1, 7, 8, -2 ]
[ -2, 0, 1, 7, 8 ]
[ 8, -2, 0, 1, 7 ]
[ 7, 8, -2, 0, 1 ] ]
Blog post: https://edspi31415.blogspot.com/2019/03/...ifted.html
For LSM, each row has the elements shifted to the left one element.
For RSM, each row has the elements shifted to the right one element.
HP Prime Program: LSM
Code:
EXPORT LSM(L0)
BEGIN
// EWS 2019-03-02
// left shift matrix
LOCAL L1,N,M0,K;
N:=SIZE(L0);
L1:=L0;
FOR K FROM 1 TO N-1 DO
L1:=CONCAT(tail(L1),head(L1));
L0:=CONCAT(L0,L1);
END;
M0:=list2mat(L0,N);
RETURN M0;
END;
HP Prime Program: RSM
Code:
EXPORT RSM(L0)
BEGIN
// EWS 2019-03-03
// right shift matrix
LOCAL L1,N,M0,K;
N:=SIZE(L0);
L1:=L0;
FOR K FROM 1 TO N-1 DO
L1:=REVERSE(CONCAT(
tail(REVERSE(L1)),
head(REVERSE(L1))
));
L0:=CONCAT(L0,L1);
END;
M0:=list2mat(L0,N);
RETURN M0;
END;
Note: The program RSM creates a circulant matrix.
Example:
list = {1, 7, 8, -2, 0}
LSM({1, 7, 8, -2, 0} returns:
[ [ 1, 7, 8, -2, 0 ]
[ 7, 8, -2, 0, 1 ]
[ 8, -2, 0, 1, 7 ]
[ -2, 0, 1, 7, 8 ]
[ 0, 1, 7, 8, -2 ] ]
RSM({1,7,8,-2,0}) returns:
[ [ 1, 7, 8, -2, 0 ]
[ 0, 1, 7, 8, -2 ]
[ -2, 0, 1, 7, 8 ]
[ 8, -2, 0, 1, 7 ]
[ 7, 8, -2, 0, 1 ] ]
Blog post: https://edspi31415.blogspot.com/2019/03/...ifted.html