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Full Version: Buon anno nuovo 2019!
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Happy new year 2019!
May you all have a happy and prosperous 2019. Happy New Year.

John
Godt nytt år

Happy new year :-)
(01-01-2019 03:14 AM)Gerson W. Barbosa Wrote: [ -> ]Buon anno nuovo duemiladiccianove!

Happy new year 2019!

Feliz ano novo, Gerson!
Just a small correction: duemiladiciannove. ;)
Ich wünsche allen ein frohes und glückliches neues Jahr 2019!

Patrik
(01-01-2019 12:10 PM)Massimo Gnerucci Wrote: [ -> ]
(01-01-2019 03:14 AM)Gerson W. Barbosa Wrote: [ -> ]Buon anno nuovo duemiladiccianove!

Happy new year 2019!

Feliz ano novo, Gerson!

Grazie, Massimo!

Probus would have pointed this out as

diciannove non diccianove

:-)

It’s interesting to see acqua was originally pronounced aqua

I remember my worst mistake regarding Italian numbers occurred when I said diciassei instead of sedici, immediately being corrected by my teacher. (Because in Portuguese we count ...onze, doze, treze, quatorze, quinze, dezesseis...)

Edited to correct yet another mistake.
Happy New Year!

Ways to calculate 2019: https://edspi31415.blogspot.com/2019/01/...-ways.html
Happy New Year!

(01-01-2019 03:57 PM)Eddie W. Shore Wrote: [ -> ]Happy New Year!

Ways to calculate 2019: https://edspi31415.blogspot.com/2019/01/...-ways.html

Also check:

My favourite fact from that video is that 2019 is the hypotenuse of a Pythagorean triple: \( 2019^2 = 1155^2 + 1656^2 \). EDIT: Fixed. Thanks to Mark Hardman for spotting the typo!
Bonne et heureuse année 2019 !
Happy New Year

Peace and Health

Long live and Prosper
(01-01-2019 07:21 PM)ijabbott Wrote: [ -> ]My favourite fact from that video is that 2019 is the hypotenuse of a Pythagorean triple: \( 2019^2 = 1152^2 + 1656^2 \).

Not to be a nit picker but, from the video, it is actually: \( 2019^2 = 1155^2 + 1656^2 \).
(01-01-2019 07:56 PM)Mark Hardman Wrote: [ -> ]
(01-01-2019 07:21 PM)ijabbott Wrote: [ -> ]My favourite fact from that video is that 2019 is the hypotenuse of a Pythagorean triple: \( 2019^2 = 1152^2 + 1656^2 \).

Not to be a nit picker but, from the video, it is actually: \( 2019^2 = 1155^2 + 1656^2 \).

Thanks for spotting that. I've edited my post to fix it.
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