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Full Version: Solve an equation as a fraqtion. Is it possible?
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Hi

I would like to solve a simple equation to two variables.
This is obvious a very simple task for the attached example but as you could imagine, i would like to do the same with much more complex equations.

So my question is, is it possible to solve such an equation to a fraqtion which consists of two variables?
I have tried with solve(...,[x/b]) but i got only an empty result.

If the prime is not able to do so, is there any othe tool out there who can do such a algebraic operation?

Thanks
The CAS is where you would do this

[attachment=6545]
(11-02-2018 08:42 AM)blevita Wrote: [ -> ]Hi

I would like to solve a simple equation to two variables.
This is obvious a very simple task for the attached example but as you could imagine, i would like to do the same with much more complex equations.

So my question is, is it possible to solve such an equation to a fraqtion which consists of two variables?
I have tried with solve(...,[x/b]) but i got only an empty result.

If the prime is not able to do so, is there any othe tool out there who can do such a algebraic operation?

Thanks

Hi,
you have to use the CAS ambient in order to do that
Best,

Aries

But its not what i have searched for ^^.
The problem is, that in my case, the "a"-part is not that simple.

I think i must give you the real example.

This is my equation:
((r1*r3*u2+r2*r3*u1)/(c2*p*r1*r2*r3+r1*r2+r1*r3+r2*r3)) = (-u2*p*c1*r3)

I want to know what u2/u1 is.
Therefore i have tried to do this:

solve(((r1*r3*u2+r2*r3*u1)/(c2*p*r1*r2*r3+r1*r2+r1*r3+r2*r3)) = (-u2*p*c1*r3),[u2/u1])

but it does not work

But its not what i have searched for ^^.
The problem is, that in my case, the "a"-part is not that simple.

I think i must give you the real example.

This is my equation:
((r1*r3*u2+r2*r3*u1)/(c2*p*r1*r2*r3+r1*r2+r1*r3+r2*r3)) = (-u2*p*c1*r3)

I want to know what u2/u1 is.
Therefore i have tried to do this:

solve(((r1*r3*u2+r2*r3*u1)/(c2*p*r1*r2*r3+r1*r2+r1*r3+r2*r3)) = (-u2*p*c1*r3),[u2/u1])

but it does not work

I got it … I think the argument has to be a variable name …
Best,

Aries

But its not what i have searched for ^^.
The problem is, that in my case, the "a"-part is not that simple.

I think i must give you the real example.

This is my equation:
((r1*r3*u2+r2*r3*u1)/(c2*p*r1*r2*r3+r1*r2+r1*r3+r2*r3)) = (-u2*p*c1*r3)

I want to know what u2/u1 is.
Therefore i have tried to do this:

solve(((r1*r3*u2+r2*r3*u1)/(c2*p*r1*r2*r3+r1*r2+r1*r3+r2*r3)) = (-u2*p*c1*r3),[u2/u1])

but it does not work

Try:

Code:
```solve(((r1*r3*u2+r2*r3*u1)/(c2*p*r1*r2*r3+r1*r2+r1*r3+r2*r3)) = (-u2*p*c1*r3), u2) Ans/u1 simplify(Ans)```

But its not what i have searched for ^^.
The problem is, that in my case, the "a"-part is not that simple.

I think i must give you the real example.

This is my equation:
((r1*r3*u2+r2*r3*u1)/(c2*p*r1*r2*r3+r1*r2+r1*r3+r2*r3)) = (-u2*p*c1*r3)

I want to know what u2/u1 is.
Therefore i have tried to do this:

solve(((r1*r3*u2+r2*r3*u1)/(c2*p*r1*r2*r3+r1*r2+r1*r3+r2*r3)) = (-u2*p*c1*r3),[u2/u1])

but it does not work

Replace u2 with u1*x and solve for x.
Thank you very much!
I think i got it

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And i love my HP-Calc.
He is much better than my old TI-NSpire. ^^
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