# Line slope calculator x+6y=10

**Straight line given by points A[4; 1] and B[10; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.1667x+1.6667

**Canonical form of the line equation:**x+6y-10 = 0

**Parametric form of the line equation:**

x = 6t+4

y = -t+1 ; t ∈ R

**Slope:**m = -0.1667

**Slope angle of line: φ =**-9°27'44″ = -0.1651 rad

**X intercept:**x

_{0}= 10

**Y intercept:**y

_{0}= q = 1.6667

**Distance line from the origin:**d

_{0}= 1.644

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(6; -1)

**Normal vector: n =**(1; 6)

**Midpoint of the segment AB: M =**[7; 0.5]

**Perpendicular Bisector equation:**6x-y-41.5 = 0

**Vector OA = (4; 1) ; |OA| = 4.1231**

**Vector OB = (10; 0) ; |OB| = 10**

**Scalar product OA .OB = 40**

**Angle ∠ AOB = 14°2'10″ = 0.245 rad**