33s solving symmetrical quadratics Message #1 Posted by bill platt on 28 July 2004, 9:45 a.m.
Hi,
Curious business. Try solving the simple expression n^26 on the 33s in the equation list.
It will return the positive root, but not the negative.
Try controlling the starting estimates by storing 10 to n, and 1 in the xregister. Still, a positive root. Try storing 1 in n, and 10 in the xregister. still, only a positive root!
On the 32sii, controlling the starting estimates "kicks" the solution over to the negative root.
Try a parabola that is shifted on the xaxis: v^2v6.
When you play with the initial estimates on this one, you DO get the negative root. Strange.
I wonder if this is related to the bizarrre "0" issue which crops up in the cartesian to polar conversion issue.?
Regards,
Bill
