|Little HP-15C challenge for the weekend|
Message #1 Posted by Ex-PPC member on 13 Mar 2003, 7:41 a.m.
Hi, here's a new, little challenge for all HP-15C fans
out there. If you think you know your 15C inside out,
this is your chance to prove it:
Assume a master-cleared HP-15C. We want to compute the value of
e^(-Pi/2) [=0.2078+] on a 15c. The direct way to do it would be:
That's 5 steps. The challenge is to do it in four steps. A simple
way would be using trigs, like this:
but that doesn't work on a master-cleared HP-15C, because this
procedure assumes radians mode and a master-cleared HP-15C defaults
to degrees , so you would need an additional RAD step at the beginning,
making 5 total. Can you do it in four ?
By the way, should you be interested in the solution to my latest Short & Sweet Math Challenge #6,
I've posted two short, commented programs for the HP-71B,
see the post S&SMC#6: An HP-71B solution in its proper thread below.