Post Reply 
Testing the mathjax engine
05-08-2016, 08:56 PM (This post was last modified: 01-31-2017 01:37 PM by emece67.)
Post: #1
Testing the mathjax engine
From \(Q = mC\Delta T\) you will get \(\Delta T = {Q\over mC}\), with \(C=4182 {J\over kg \Delta K}\) being the specific heat of water at 20ºC. With this you get \[\Delta T = {25000 J\over 2kg · 4182 {J\over kg \Delta K}} = 2.989 \Delta K\]

Then the final temperature will be: \(T_0+\Delta T = 20 ºC + 2.989 \Delta K =\) Inconsistent units.

César - Information must flow.
Find all posts by this user
Quote this message in a reply
02-19-2017, 03:33 PM
Post: #2
RE: Testing the mathjax engine
$\frac{N_i}{D_i}=\frac{N_{i-1}}{D_{i-1}}+\frac{1}{F_i}=\frac{F_i\cdotN_{i-1}+D_{i-1}}{D_{i-1}\cdotF_i}$
Find all posts by this user
Quote this message in a reply
02-19-2017, 03:35 PM
Post: #3
RE: Testing the mathjax engine
(05-08-2016 08:56 PM)emece67 Wrote:  From \(Q = mC\Delta T\) you will get \(\Delta T = {Q\over mC}\), with \(C=4182 {J\over kg \Delta K}\) being the specific heat of water at 20ºC. With this you get \[\Delta T = {25000 J\over 2kg · 4182 {J\over kg \Delta K}} = 2.989 \Delta K\]

Then the final temperature will be: \(T_0+\Delta T = 20 ºC + 2.989 \Delta K =\) Inconsistent units.
\frac{N_i}{D_i}=\frac{N_{i-1}}{D_{i-1}}+\frac{1}{F_i}=\frac{F_i\cdotN_{i-1}+D_{i-1}}{D_{i-1}\cdotF_i}
Find all posts by this user
Quote this message in a reply
02-19-2017, 03:40 PM
Post: #4
RE: Testing the mathjax engine
(05-08-2016 08:56 PM)emece67 Wrote:  From \(Q = mC\Delta T\) you will get \(\Delta T = {Q\over mC}\), with \(C=4182 {J\over kg \Delta K}\) being the specific heat of water at 20ºC. With this you get \[\Delta T = {25000 J\over 2kg · 4182 {J\over kg \Delta K}} = 2.989 \Delta K\]

Then the final temperature will be: \(T_0+\Delta T = 20 ºC + 2.989 \Delta K =\) Inconsistent units.

\(\frac{N_i}{D_i}=\frac{N_{i-1}}{D_{i-1}}+\frac{1}{F_i}=\frac{F_i · N_{i-1}+D_{i-1}}{D_{i-1} · F_i}\)

JÍHÁÁÁÁ! Big Grin
Find all posts by this user
Quote this message in a reply
02-19-2017, 08:14 PM (This post was last modified: 02-19-2017 08:14 PM by Luigi Vampa.)
Post: #5
RE: Testing the mathjax engine
(05-08-2016 08:56 PM)emece67 Wrote:  [•••]
Then the final temperature will be: \(T_0+\Delta T = 20 ºC + 2.989 \Delta K =\) Inconsistent units.
I might be wrong, I haven't been involved in thermal issues since my second course in the University.
Kelvin degrees = Centigrade degrees + the absolute zero offset
Offsets are canceled in the Delta, so that there would be no incoherence. The same Delta in Centigrade degrees would have the very same value.
Fahrenheit degrees are another story, you know.

Saludos Saluti Cordialement Cumprimentos MfG BR + + + + +
Don Luigi
KindleFire7 Android Free42 '<3' I + + + +
Find all posts by this user
Quote this message in a reply
Post Reply 




User(s) browsing this thread: 1 Guest(s)