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Little explorations with HP calculators (no Prime)
03-28-2017, 08:15 PM (This post was last modified: 03-29-2017 08:47 AM by pier4r.)
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RE: Little explorations with the HP calculators
(03-28-2017 07:32 PM)Han Wrote:  Draw a line segment from the point of tangency (where the circle touches the radial segments of length 10) toward the center of the inner circle. This length is d/2, and the line segment we created is perpendicular to the segments of length 10. (You can produce a square whose diagonal lies at the center of the two circles, and whose side lengths are d/2.)

Understood. I thought about that but I could not prove... frick. I relied too much on the visual image. Instead of thinking that when a line is tangent to a circle then the radius is perpendicular to it (otherwise the circle would pass through the line), I looked at the picture and I sad "hmm, here I cannot build a square with the radius, I do not see perpendicularity". So it was actually trivial but I relied too much on the visual hint.

Damn me. Well, experience for the next time.


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RE: Little explorations with the HP calculators - pier4r - 03-28-2017 08:15 PM

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