An old member returns...

[Gerson W. Barbosa]

(02-22-2015 04:50 PM)walter b Wrote:  

(02-20-2015 02:51 PM)Thomas Radtke Wrote:  The signature already told the story ... if you know V. and a little physics.

Still waiting for an answer telling me what the claim SQRT(VA) = W should have to do with physics. TIA for enlightenment.

d:-?

All my fault because of putting 1 instead of 10 in line 07 and thus getting 32, that is, "W", instead of 45... Again, apologies!

Code:


00 { 34-Byte Prgm }
01>LBL "VA"
02 32                        ; start with base 32, since V = 31 (A = 10, B = 11, ...)
03>LBL 00
04 RCL ST X
05 31
06 ×
07 10
08 +                       
09 SQRT
10 FP                        ; check whether 31*base + 10 is a perfect square 
11 X=0?                                   
12 GTO 01                    ; if ok go show square root and base (stack registers X and Y, respectively)
13 X<>Y
14 1                         ; else
15 +                         ;     try next base
16 GTO 00
17>LBL 01
18 X<>Y
19 LASTX
20 .END.  [code]

BTW, by the same reasoning the square root of JFG is 330646 and the square root of GWB is 14944740. I haven't been able to find the square roots of WB and TR, but perhaps I haven't searched long enough.

Gerson.

Edited to add comments to the code

P.S.: Sqrt(GWB) above is wrong, but at least Sqrt(JFG) is correct :-)
P.P.S: I've just found out a member here has Sqrt = O(24) that is, 24 in base 34. Someone else with an even lower square root? :-)