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An old member returns...
02-22-2015, 04:41 PM (This post was last modified: 02-22-2015 04:45 PM by Gerson W. Barbosa.)
Post: #22
RE: An old member returns...
(02-22-2015 11:47 AM)J-F Garnier Wrote:  
(02-20-2015 02:51 PM)Thomas Radtke Wrote:  The signature already told the story ... if you know V. and a little physics.

(02-20-2015 09:27 PM)Gerson W. Barbosa Wrote:  Actually VA equals W only when var equals zero [ VA = sqrt(W^2 + var^2) ]. This has nothing to do with VA's little riddle though. The square root of VA might be W for a quite different reason, if I got him right. Also, VA as we know him is a real entity, not an apparent one. :-)
P.S.: I thought you were referring to another kind of VA. Yes, your VA does equal W. Sorry!

As an electric engineer and knowing Valentin, I can only share your point :-)

In one of his famous S&SMC , Valentin asked to find a solution on the HP-71B to the equation:
Abs(Ln(x*x)-Ln(x^2)) > 4.012007 (BTW, I found a solution ...)
In the same way, is it possible to have square of VA significantly different from the product of VA by VA?

Let's take all this with humour... :-)

J-F

I've made a great mistake (please see my updated reply to Valentín). So one possible answer to the square root of VA is 45, NOT W, if my line of thought matches Valentín's.

I am sorry for having misled all of you from the solution. Again, my apologies!

This and the answer to the first problem might give a hint to both solutions, in case no one has figured them out yet.

Best regards,

Gerson.
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Messages In This Thread
An old member returns... - rprosperi - 02-14-2015, 10:08 PM
RE: An old member returns... - rprosperi - 02-15-2015, 03:43 PM
RE: An old member returns... - walter b - 02-20-2015, 08:24 PM
RE: An old member returns... - J-F Garnier - 02-22-2015, 11:47 AM
RE: An old member returns... - Gerson W. Barbosa - 02-22-2015 04:41 PM
RE: An old member returns... - walter b - 02-22-2015, 04:50 PM
RE: An old member returns... - bshoring - 02-20-2015, 06:14 AM
RE: An old member returns... - Paul Dale - 02-20-2015, 06:56 AM
RE: An old member returns... - Jeff_Kearns - 02-24-2015, 02:17 AM
RE: An old member returns... - Jeff_Kearns - 02-24-2015, 09:07 PM



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