Improper integral
|
06-12-2014, 08:59 AM
(This post was last modified: 06-12-2014 09:58 AM by Wes Loewer.)
Post: #22
|
|||
|
|||
RE: Improper integral
(06-11-2014 07:22 PM)Mark Hardman Wrote:(06-11-2014 07:01 PM)HP67 Wrote: Why does the op say it should be 75/4?The asymptote is at x=1, I'm not sure why the OP thinks there would be a real solution in the interval 0..1. Because using the real root definition, the 5th root of a negative real is a negative real. This improper integral can be evaluated be splitting the interval at the asymptote. Integrating from 0 to 1 gives a result of -5/4 Integrating from 1 to 33 gives a result of 20 20-5/4 = 75/4 |
|||
« Next Oldest | Next Newest »
|
User(s) browsing this thread: 1 Guest(s)