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Testing the mathjax engine
06-11-2017, 10:56 AM
Post: #6
RE: Testing the mathjax engine
(02-19-2017 03:40 PM)Csaba Tizedes Wrote:  
(05-08-2016 08:56 PM)emece67 Wrote:  From \(Q = mC\Delta T\) you will get \(\Delta T = {Q\over mC}\), with \(C=4182 {J\over kg \Delta K}\) being the specific heat of water at 20ºC. With this you get \[\Delta T = {25000 J\over 2kg · 4182 {J\over kg \Delta K}} = 2.989 \Delta K\]

Then the final temperature will be: \(T_0+\Delta T = 20 ºC + 2.989 \Delta K =\) Inconsistent units.

\(\frac{N_i}{D_i}=\frac{N_{i-1}}{D_{i-1}}+\frac{1}{F_i}=\frac{F_i · N_{i-1}+D_{i-1}}{D_{i-1} · F_i}\)

JÍHÁÁÁÁ! Big Grin

From these equations (\(\beta\) in radian):
\(R_2 · \beta=2 · r · \pi\), and

\((R_2+s) · \beta=2 · R · \pi\)

we get:
\(R_2=\frac{\frac{h}{cos \alpha}}{\frac{R}{R-h_x}-1}\), and

\(\beta=\frac{2 · (R-h_x) · \pi}{R_2}\)
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Testing the mathjax engine - emece67 - 05-08-2016, 08:56 PM
RE: Testing the mathjax engine - Csaba Tizedes - 06-11-2017 10:56 AM



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