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Question about CAS and Graphing
11-22-2014, 02:31 PM
Post: #13
RE: Question about CAS and Graphing
(11-22-2014 03:01 AM)jte Wrote:  If you define f as a function in the CAS

(for example, by entering "f(x):=1/2*x^2")

then in the Function Symbolic View entering and checking

F1(X)=f(X)

should also bring up a parabola in the Function plot view.

There is an issue with moving non-floating-point values from the CAS to the numeric (Function, Home, etc.) environment (this can be seen with the above example by going to the Function Numeric View). To ameliorate this issue you can uncheck the "Exact" setting in the CAS Settings screen.

Plotting won't be as fast as F1(X)=1/2*X^2 due to the many round trips between the CAS and numeric environments.

This is unnecessary. In CAS, simply type:

F1:=f('X');

which evaluates f at the symbolic value 'X' and properly provides a formula for F1.

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Messages In This Thread
RE: Question about CAS and Graphing - Han - 09-24-2014, 10:14 PM
RE: Question about CAS and Graphing - Han - 09-25-2014, 01:35 PM
RE: Question about CAS and Graphing - jte - 11-22-2014, 03:01 AM
RE: Question about CAS and Graphing - Han - 11-22-2014 02:31 PM
RE: Question about CAS and Graphing - jte - 11-23-2014, 06:31 PM
RE: Question about CAS and Graphing - Han - 11-23-2014, 08:42 PM
RE: Question about CAS and Graphing - jte - 11-26-2014, 06:02 AM
RE: Question about CAS and Graphing - Han - 11-22-2014, 02:16 PM
RE: Question about CAS and Graphing - Han - 11-22-2014, 07:26 PM
RE: Question about CAS and Graphing - Han - 11-23-2014, 08:41 PM
RE: Question about CAS and Graphing - Han - 11-24-2014, 11:47 AM
RE: Question about CAS and Graphing - Han - 11-24-2014, 01:29 PM
RE: Question about CAS and Graphing - Han - 11-24-2014, 02:12 PM



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