HP Forums

Full Version: Beauty of Equations?
You're currently viewing a stripped down version of our content. View the full version with proper formatting.
Article from today's Guardian:

https://www.theguardian.com/science/2016...-beautiful

Note error in quiz.

Any candidates for attractive equations?
Attractive they may not be but to me the superb pinnacle is captured by the Maxwell equations, followed shortly by the Navier-Stokes equations... this is of course just a personal bias.
(11-21-2016 12:14 PM)Gerald H Wrote: [ -> ]Note error in quiz.

Oh yes, well spotted. Everyone knows that it should be \(e^{i\tau} = 1\)
;-)
(11-21-2016 01:26 PM)Ángel Martin Wrote: [ -> ]Attractive they may not be but to me the superb pinnacle is captured by the Maxwell equations, followed shortly by the Navier-Stokes equations... this is of course just a personal bias.

Agreed! Even though Nature seems to be nonlinear, Electrodynamics is fully captured by the pure linear Maxwell Equations. Also, The Navier-Stokes Equations of Fluid Dynamics are "just" seminlinear. However, the proof of the global existence and uniqueness of smooth solutions to the 3D Navier-Stokes Equation is still lacking, it's a Millenium-Problem! Long time ago I did my math. PhD Thesis on timewise Approximation of the Stokes-Equations (which is the Navier-Stokes without convecive term and thus it is linear). Learned to love this set of Equations! Has been exciting years :-)
Here's a film of Hannah Fry's choice:

https://www.theguardian.com/science/vide...axies-form
(11-22-2016 05:25 PM)Gerald H Wrote: [ -> ]Here's a film of Hannah Fry's choice:

https://www.theguardian.com/science/vide...axies-form

Great! Thanks for sharing!! :-)
(11-21-2016 05:10 PM)BruceH Wrote: [ -> ]
(11-21-2016 12:14 PM)Gerald H Wrote: [ -> ]Note error in quiz.

Oh yes, well spotted. Everyone knows that it should be \(e^{i\tau} = 1\)
;-)

I think that would be \(e^{i\tau/2} = -1\), (or preferably, \(e^{i\tau/2} + 1 = 0\)), which kinda sorta shows why tau is wrong, i.e., messes up Euler's identity.
I've always felt attracted to transcendental calculations, so I choose:

M=E-e*sin(E)
Reference URL's