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Dear all, thank you for your patience in advance.

Please, let me ask you a couple more question about the 34s:

I would like to integrate a function like \(f(x) = \frac{1}{x+a}\) where \(a\) is as large as 1000. Not knowing exactly how things worked in previous HP calcs, I naively typed 1500 for \(a\) directly into the program, well, you know what happened.
The manual says that integers (say \(n\)) can be keyed in using the # symbol, however, it also states that \(0\leqslant n \leqslant 255\). Now comes the noobie question:

Do I have to modify \(n\) by assigning, for example, 250 to it and multiply by 6 to get 1500? Or I am missing something here?

Thank you

Marcio

EDIT: Alternatively, I could also assign a register to \(a\) before using it in the program, in case \(a\) is a prime number and greater than 255.

I see various ways to accomplish this:

1. You can just type the number into your program:

LBL 00
1
5
0
0
+
1/x
RTN

2. If your number is a multiple of 10 use:

LBL 00
# 150
SDL 1
+
1/x
RTN

3. The most flexible approach uses register 00 to hold a:

LBL 00
RCL+ 00
1/x
RTN

Yeap, storing \(a\) and calling it from the program is the way to go.

Thanks.