08-25-2018, 10:29 AM
This program calculate Binomial Distribution using three known variables.
Binomial Distribution formula:
f(x) = (nCx)(p^x)(1-p)^n-x
where n and x are integers,
nCx = n! / x!(n-x)! // n choose x Combination
0 ≤ x ≤ n ≤ 69 and 0 < p < 1
n = number of times experiment run
x = number we want
p = probability of one specific run
Procedure:
n [ENTER] x [ENTER] p [R/S]
Example: FIX 9
Sam says
"70% choose chicken, so 7 of the next 10 customers should choose chicken"
What are the chances Sam is right?
n = 10 // Total of 10 customers
x = 7 // 7 out of 10
P = 0.7 // 70% choose chicken
10 [ENTER] 7 [ENTER] .7 [R/S] display 0.266827932
Answer: about 27% chance
Program: Binomial Distribution
Gamo
Binomial Distribution formula:
f(x) = (nCx)(p^x)(1-p)^n-x
where n and x are integers,
nCx = n! / x!(n-x)! // n choose x Combination
0 ≤ x ≤ n ≤ 69 and 0 < p < 1
n = number of times experiment run
x = number we want
p = probability of one specific run
Procedure:
n [ENTER] x [ENTER] p [R/S]
Example: FIX 9
Sam says
"70% choose chicken, so 7 of the next 10 customers should choose chicken"
What are the chances Sam is right?
n = 10 // Total of 10 customers
x = 7 // 7 out of 10
P = 0.7 // 70% choose chicken
10 [ENTER] 7 [ENTER] .7 [R/S] display 0.266827932
Answer: about 27% chance
Program: Binomial Distribution
Code:
01 STO 1
02 Rv
03 STO 2
04 Rv
05 STO 3
06 RCL 1
07 RCL 2
08 Y^X
09 1
10 RCL 1
11 -
12 RCL 3
13 RCL 2
14 -
15 Y^X
16 LSTx
17 n!
18 ÷
19 x
20 RCL 3
21 n!
22 x
23 RCL 2
24 n!
25 ÷
Gamo