Re: CEILING function substitute for 35s Message #4 Posted by Eduardo Duenez on 11 Sept 2007, 4:21 p.m., in response to message #2 by Meenzer
Not really so! CEIL(x) is *equal* to FLOOR(x) if x is an integer!
I don't have a 35s yet but CEIL(x) = -FLOOR(-x), so a solution is to write a short program executing
NEG FLOOR NEG
Eduardo
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