The Museum of HP Calculators

HP Forum Archive 05

 Where can get info on Technical Applications ManualMessage #1 Posted by Mike Burns on 15 Feb 2001, 8:22 p.m. Seeking all people who have info & accessibility to this Manual: Step by Step Solutions For Your HP Calculator Technical Applications HP-19B & HP-27S Reorder #00027-90053 Printed in Canada Nov198 ISPN#088698000205

 Right hereMessage #2 Posted by Jim L on 15 Feb 2001, 8:38 p.m.,in response to message #1 by Mike Burns I see that one listed on the CDs available on this site. See http://www.hpmuseum.org/software/swcd.htm for the whole list.

 Re: Right hereMessage #3 Posted by Mike Burns on 16 Feb 2001, 1:06 p.m.,in response to message #2 by Jim L Thanks Jim L. Maybe you or some one out there can help me further. Re: calculater manuals CD's 1-3 where can I locate a table of contents for these manuals & which Reference Manual,Advanced Functions Manual,and Technical Applications Manual would be most suitable for a HP17BII especially the equation solver. I will give an example of an equation on a new posting soon. I have combined 2 equations into one.

 Equation problem using HP17BIIMessage #4 Posted by Mike Burns on 16 Feb 2001, 2:12 p.m.,in response to message #3 by Mike Burns The original book equation for (speed walking aerobic fitness points) PT=(Dx60/T)-1)xD-1 e.g. (2x60/30)-1)x2-1=5 points Where PT=points, D=distance(2miles), & T=time(30 minutes). My equation: PM=seconds per mile(based on 13 minute miles eg 13:21 where PM=21 seconds) I used an equation for distance to combine two equations into one: D=(T/(PM/60+13)x60. Therefore; PT=(T/(PM/60+13)x60)/T-1x(T/(PM/60+13)x60)-1. When working out equation in a step by step procedure it only works out properly up to PM=(T/(PM/60+13)x60)/T-1 when I put the rest of the equation in the answer is way off. What am I doing wrong?

 A guessMessage #5 Posted by Dave Hicks on 16 Feb 2001, 3:26 p.m.,in response to message #4 by Mike Burns I don't really understand what you're doing but I think you might want: PT=((T/(PM/60+13)x60)/T-1)x((T/(PM/60+13)x60)-1) That's what you had with some more parens where I think you might need them.

 Or perhapsMessage #6 Posted by Dave Hicks on 16 Feb 2001, 3:42 p.m.,in response to message #5 by Dave Hicks PT=((T/(PM/60+13)x60)/T-1)x(T/(PM/60+13)x60)-1 This one most closely matches your original expression.

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